msimard8
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Hmmm I seem to be stumped on this question.
Prove that the sum of the exterior angles at opposite verticies of any quadrilateral is equal to the sum of the interior angles at the other two verticies?
I don't really have a start because I can't seem to get my mind wrapped around where to begin.
I know the sum of exterior angles is 360 degrees. And the sum of interior angles in a quadilateral is equal to 360 degrees aswell.
I don't know where to go from there.
Hint or Help please
thanks
Prove that the sum of the exterior angles at opposite verticies of any quadrilateral is equal to the sum of the interior angles at the other two verticies?
I don't really have a start because I can't seem to get my mind wrapped around where to begin.
I know the sum of exterior angles is 360 degrees. And the sum of interior angles in a quadilateral is equal to 360 degrees aswell.
I don't know where to go from there.
Hint or Help please
thanks