Prove that a linear operator is indecomposable

toni07
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Homework Statement



Let V be a fi nite-dimensional vector space over F, and let T : V -> V be a linear operator. Prove that T is indecomposable if and only if there is a unique maximal T-invariant proper subspace of V.

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The Attempt at a Solution


I tried using the definition of decomposable with respect to matrices, but I can't manipulate it to answer this question.
 
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Start by providing us the definition of "indecomposable operator" and "T-maximal".
 
A n×n matrix A is decomposable if there exists a nonempty proper subset I⊆{1,2,...,n} such that aij=0 whenever i∈I and j∉I.

I only know the definition of maximal vector which is: A vector z such that the minimal polynomial of the operator T with respect to z = the minimal polynomial of the operator T, is called a maximal vector.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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