Prove that the greatest angle is 120

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The discussion focuses on proving that the greatest angle of a triangle, defined by the sides x^2+3x+3, 2x+3, and x^2+2x, is 120°. Participants emphasize that the longest side determines the greatest angle, which varies based on the value of x. It is established that for positive x, one side consistently remains the longest, allowing for the application of the cosine rule. Graphing the side lengths reveals that their order can change depending on the interval of x, but ultimately, the conditions for the triangle's sides must be met. The conclusion is that with x positive, the proof can be effectively demonstrated.
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Homework Statement


The sides of a triangle are x^2+3x+3, 2x+3,x^2+2x. Prove that the greatest angle of the triangle is 120°.

Homework Equations



The Attempt at a Solution


The greatest angle is the one opposite to the greatest side. But how to decide which one is greatest side? Also the sides are variable.
 
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The side lengths must be positive numbers. Is x2+3x+3>x2+2x? Is x2+3x+3>2x+3?

ehild
 
Assuming x > 0, it should be obvious which is the longest side. (But you can't say in general which is the shortest.)
Do you know the cosine rule relating lengths of sides of a triangle?
 
utkarshakash said:

Homework Statement


The sides of a triangle are x^2+3x+3, 2x+3,x^2+2x. Prove that the greatest angle of the triangle is 120°.

Homework Equations



The Attempt at a Solution


The greatest angle is the one opposite to the greatest side. But how to decide which one is greatest side? Also the sides are variable.
It depends on the value of x. If you graph y1 = x^2 + 3x + 3, y2 = x^2 + 2x, and y3 = 2x + 3, two of the graphs are parabolas and one is a straight line. On the interval [0, 1], the largest values are for y1 = x^2 + 3x + 3 and the smallest are for y2 = x^2 + 2x. For the interval [-1, 0] the order is different.
 
Mark44 said:
It depends on the value of x.
No, it turns out not to.
 
Mark44 said:
It depends on the value of x.
haruspex said:
No, it turns out not to.
By what I said, I meant that the values of the three expressions depend on x. As you said, one of the sides is the longest, but for other two sides, it depends on which interval you're looking at.
 
Turns out x has to be positive, otherwise one of the sides has a negative length.
And if x is positive, there is only one side that can be longest.

I found the results were even more impressive when I worked it through...
 
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