Proving d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

chill_factor
Messages
898
Reaction score
5

Homework Statement



L = lambda.

Prove: d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

Homework Equations



?

The Attempt at a Solution



I did this as an analogy with function of numbers, but don't know how to extend this to matricies. for example:

lets say A = f(L)

d(f(L)^-1)/dL = - (f(L)^-2*d(f(L))/dL = -(A^-1)*dA/dL*(A^-1)

But what is the matrix form?
 
Physics news on Phys.org
chill_factor said:

Homework Statement



L = lambda.

Prove: d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

Homework Equations



?

The Attempt at a Solution



I did this as an analogy with function of numbers, but don't know how to extend this to matricies. for example:

lets say A = f(L)

d(f(L)^-1)/dL = - (f(L)^-2*d(f(L))/dL = -(A^-1)*dA/dL*(A^-1)

But what is the matrix form?

I'll use x instead of L, and let B(x) = Inv(A(x)); thus, A(x)*B(x) = I (identity matrix). Take the derivative.

RGV
 
Ray Vickson said:
I'll use x instead of L, and let B(x) = Inv(A(x)); thus, A(x)*B(x) = I (identity matrix). Take the derivative.

RGV

Thanks greatly.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top