Proving Isomorphism of Heisenberg Group over Finite Field

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Homework Statement


Let H be the subgroup of GL(3, \mathbb{Z}_3) consisting of all matrices of the form \left[ \begin{array}{ccc} 1 & 0 & 0 \\ a & 1 & 0 \\ b & c & 1 \end{array} \right], where a,b,c \in \mathbb{Z}_3. I have to prove that Z(H) is isomorphic to \mathbb{Z}_3 and that H/Z(H) is isomorphic to \mathbb{Z}_3 \times \mathbb{Z}_3.


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The Attempt at a Solution


I'm really not sure how to begin with this. I started by taking two arbitrary matrices h and k from H and doing hk = kh to see what a matrix in Z(H) would have to look like, but I didn't really get anywhere with that. My initial instinct would be to just define a mapping from Z(H) to \mathbb{Z}_3, but I'm not sure how to do that, since I can't figure out what's in Z(H). Is there a better way to do this?
 
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These groups are known in literature as Heisenberg group over a finite field. It is generally written in the upper triangular matrix form. But that does not make any difference.
So let me define a typical element of this field as A=\langle a,b,c\rangle where a, b, c have the same meaning and order as you have written in the definition of the group. Let C=\langle x,y,z\rangle\in Z(H). Calculate AC and CA, and equate them...


Edited by Hurkyl: please don't give complete solutions to problems...[/color]
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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