Proving Linear Independence: Fixed t€R with {u,v}CR^2

atakel
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Let t€R be fixed. Show that {u,v}CR^2 with u=(cost,sint), v=(-sint,cost) is a linearly inpedendent set.
 
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My advice to you is to set up vectors u,v as a 2x2 matrix and plug in values for t;

then how do you conclude that a matrix has linearly independent vectors?
 
ı don't know ://
 
Do you know what "the rank" of a matrix is?
 
I uploadded the original question, there is no information about 'the rank'. In addition that I don't know how to solve the others.
 

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So you've never heard of the rank of a matrix? Hmm, that makes it a bit more difficult.

Anyway, our u and v are independent iff

\alpha u+\beta v=0~\Rightarrow~\alpha=\beta=0

were alpha and beta are real number.
So, how do you proceed. You assume that there exists alpha and beta such that

\alpha (\cos t,\sin t)+\beta (-\sin t,\cos t)=(0,0)

this will give you a system of two equations and two unknowns (the alpha and beta).
Solve this system. If you find \alpha=\beta=0, then our u and v are independent.
 
thank u=)
if u have any idea about other questions, can u help me?
I didn't take a linear cource.. Solving these questions is really diffucult for me://
 
Yes, Id be happy to help you with these questions. But first you need to show me what you did yourself to try and solve these questions...
 
Actually, at first I started to study ''Partial Differential Equations in Action, Salsa'' but my backround is not enough to understand all subjects. Now I turned back and I started studying linear algebra..
For now, I don't have any idea about solving these questions. I have one week to learn all these subjects..
 
  • #10
I'm sorry to say this, but you should first learn linear algebra and then start worrying abou th questions. We cannot help you until you learned some linear algebra :frown:
 
  • #11
ok thank u:(
 
  • #12
But hey, don't despair. If you're stuck on something, you can always ask us :smile:
 
  • #13
=) I am going to finish all subjects asp.. anf then I will turn back with my new questions.. thank u very much=)
 
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