Proving Maximum Volume of a Right Circular Cone: Optimization Problem Solution

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Homework Statement



A right circular cone of base radius r and height h has a total surface area S and volume V . Show that 9V2=r2(S2-2pir2S) . (i can do this part) . Hence or otherwise , show that for a fixed surface area S , the maximum volume of the cone occurs when its semi-vertical angle , theta is given by tan theta=1/2(root 2)

The Attempt at a Solution



From the proven equation ,

9V2=r2(S2-2pir2S)

Differentiate this wrt to r ,

dV/dr=(2S2r-8pi Sr3)/(18V)

dV/dr=0 , S=4pi r2 , substitue S with the area of cone , then
tan theta=r/h=1/(2 root 2)

This is my question , how do i prove that its a maximum ?
 
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when you took the derivative of the Volume function and set it equal to zero you are finding a critical value.
There are a couple ways to test whether it is a local min or max. The second derivative test is one of them.

note: I have to check your derivation; not that I am doubting it or anything.
 
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