Proving Q/Z isomorphic to U∗: Roots of Unity in C

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Show that Q/Z is isomorphic to the multiplicative group U∗ consisting of all roots of unity
in C. (That is, U∗ = {z ∈ C|zn= 1 for some n ∈ Z+}.)

I don't really understand how to prove this isomorphism
 
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Use the first isomorphism/homomorphism theorem, which states that if you have a homomorphism f from G to G', then there is an isomorphism from the quotient group G/H to the image f(G), where H = Ker f.

So the idea is to exhibit a homomorphism between Q and U* whose kernel is precisely the integers. To do this, first figure out what the identity in U* is (because we need to show that our eventual homomorphism takes the integers to this identity in U*). It's really helpful in this problem if you already know precisely what the n-th roots of unity are (i.e. you know the explicit formula).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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