Proving Sequence Convergence: ||s_n|-|L|| < epsilon

tarheelborn
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Homework Statement


For any a, b in R, show that ||a|-|b|| <= |a-b|. Then prove that {|s_n|} converges to |L| if {s_n} converges to L.

Homework Equations





The Attempt at a Solution


For the first part, ||a|-|b|| = |a-b| by the triangle inequality. For the second part, ||s_n|-0| < epsilon implies that |s_n -0| < epsilon, but I am not sure how to work that around to the L's.
 
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tarheelborn said:
For the first part, ||a|-|b|| = |a-b| by the triangle inequality.

What? For example:
\big|\,|2|-|-2|\,\big| = |2-(-2)|
?
 
Get the | |a| - |b| | \leq |a - b| right first. The second part just follows by the Squeeze Theorem, or more simply, just "shove in the epsilons" if you know what I mean.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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