Proving the Fundamental Theorem of Calculus Twice

steelers2147
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Homework Statement


Complete the proof by using the Fundamental Theorem of Calculus TWICE to establish
\int_c^d(\int_a^b f _{x}(x,y)dx)dy=...=\int_a^b(\int_{c}^{d}f_{x}(x,y) dy)dx



Homework Equations


I know that the FTC states that if g(x)=\int_a^x(f), then g'=f


The Attempt at a Solution


I'm not sure how to use this fact to get the proof started. Any guidance would be appreciated.
 
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Fixed your integral. You had [ \tex] rather than [ /tex].
steelers2147 said:

Homework Statement


Complete the proof by using the Fundamental Theorem of Calculus TWICE to establish

<br /> \int_c^d(\int_a^b f _{x}(x,y)dx)dy=...=\int_a^b(\int_{c}^{d}f_{x}(x,y)dy)dx <br />



Homework Equations


I know that the FTC states that if g(x)=\int_a^x(f), then g'=f


The Attempt at a Solution


I'm not sure how to use this fact to get the proof started. Any guidance would be appreciated.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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