Proving the Order of a Tensor: Transformation Laws and Quotient Theorem

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Homework Statement



The equation of a quadric surface takes the form

a_i_jx_ix_j = 1, a_i_j = a_j_i

relative to the standard coordinate axes. Under a rotation of axes the equation of the surface becomes

a'_i_jx'_ix'_j = 1

By considering the coordinates x_i as components of position vectors, show that the coefficients a_i_j are components of a second order tensor

(i) using transformation laws;
(ii) using the quotient theorem

Homework Equations





The Attempt at a Solution



I need a bit of a kick-start on this one.
I'm guessing my objective will be to show that:

a'_i_j = l_i_ml_j_na_m_n where l_i_j is an entry in the matrix representing the rotation.

but it's not clear to me how to relate a, l and x.
 
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In the equation a'ijx'ix'j = 1, write x' in terms of x. In the resulting equation, can you identify an expressionis that must be equal to aij? This will tell you how aij are related to a'ij, i.e. how the components of a transform.
 
dx said:
In the equation a'ijx'ix'j = 1, write x' in terms of x. In the resulting equation, can you identify an expressionis that must be equal to aij? This will tell you how aij are related to a'ij, i.e. how the components of a transform.

Thanks for your response. Rewriting x' in terms of x I get:

a_i_j'x_i'x_j' = 1 => a_i_j'l_i_mx_ml_j_nx_n = 1 = a_m_nx_mx_n
=> a_i_j'l_i_ml_j_n = a_m_n

This is close, but it's not clear to me how to shuffle the elements of the rotation matrix L from the LHS to the RHS. I also suspect the symmetry of a was mentioned for a reason, and that it's likely that it suggests a property that I should be taking advantage of.
 
Would really appreciate some help on this. I'm studying remotely and have no other students to refer to, and the course tutor seems to be on extended leave. I have about 24 hours before the last mail pick-up to make the assignment due date. Any help fully appreciated.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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