PT symmetry breaking in optical systems

Ricvil
Messages
10
Reaction score
0
There are very results published about PT symmetry breaking in optical systems, with effects like anysotropical transmission resonance in waveguides.
But if PT symmetry is broken in a optical system and CPT symmetry must always be respected, then what C symmetry is broken in a optical system?
 
Physics news on Phys.org
Do you have a reference?
I guess the breaking is related to material properties - the material does not have to be symmetric. Exact T transformation would mean you have to replace matter-waveguides by antimatter-waveguides - I doubt they did that!
 
A matter effect. The matter is not symmetric, there is no PT violation on a fundamental level.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top