Pulling vs Pushing: Which is Easier for Moving Chairs?

  • Thread starter Thread starter coolone_888
  • Start date Start date
AI Thread Summary
Moving a chair is easier by pulling rather than pushing due to the vertical force component created when pushing, which increases friction. When pushing, the downward force on the chair's legs adds to the normal force, resulting in greater resistance against movement. In contrast, pulling the chair minimizes this vertical force, reducing friction and making it easier to slide. If both actions were performed perfectly in the same plane, the difficulty would be equal, but practical application shows pulling is more efficient. Ultimately, the mechanics of force and friction favor pulling as the easier method for moving chairs.
coolone_888
Messages
5
Reaction score
0
Why is it easier to move a chair across the floor by pulling then by pushing it?
 
Physics news on Phys.org
push the chair at the bottom near it's legs, then try again ;)

also when pushing, you're pushing down (vertical component of force) so creates more friction because F=\mu.R etc etc etc

if you were pulling and pushing perfectly in the plane of the chair then it would be just as easy/hard etc etc...
someone else will put that into English for you
 
so it is easier to pull a chair across the floor because if you push you just add more friction?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top