Push up weight distrubtion problem

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SUMMARY

The discussion centers on calculating the weight distribution during push-ups for an 80kg individual, with specific distances from hands and feet. The center of mass is located 60cm from the hands and 1m from the feet, with a total distance of 1.6m between them. To solve the problem, participants emphasize the use of force and torque equations, establishing that the forces at the hands and feet must equal the total weight, while the torques must balance. This leads to a system of two equations with two unknowns to determine the weight supported by each point.

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Homework Statement



While doing push ups part of the weight of an 80kg young man is supported by his hands and part by his feet. His center mass is located 60cm from his hands and 1m from his feet. (The hand ot feet distance is 1.6m) How much of the total weight is supported by his hands? How much of the weight is supported by his feet? Use the feet as the pivotal point.

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The Attempt at a Solution



I don't even know where to start...It's just completely escaped my mind. This was a question on a test we had last week and I'm quite anxious to figure out how to do it.
 
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You need to use the forces and the torques to figure this out.

Knowing that the forces of the hands and feet are equal to the weight and that the torques likewise cancel out, you should have 2 equations and 2 unknowns.
 

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