PV graph question (trying to determine the work)

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SUMMARY

The discussion centers on calculating the work done by a system represented in a PV diagram, specifically from points A to C. The user initially attempted to calculate work using the area under the curve method but arrived at an incorrect value of 1596J. The correct approach involves using the formula for work done, which is pressure multiplied by the change in volume (W = P * ΔV). The user was advised to focus on the correct interpretation of the areas under the graph for accurate calculations.

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Homework Statement


Look at the PV diagram of a system above. (attached) The units for P and V are atmospheric pressure atm and liter L. Process A to B and B to C are straight lines on it.
How much is the work done by the system from A to C in J?



Homework Equations


i know that work is the area under the graph, but when i add up areas, answer is wrong for some reason??


The Attempt at a Solution


W = .5(4*3) + .5(4*1.5) * 152J
= 1596J

this is wrong though
?

 

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>>>>Work Done is...[ p*delta V] i.e. pressure multiplied by CHANGE IN VOLUME.

This is enough for a hint...^^^
 

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