Qestion about pressure transducer

AI Thread Summary
The discussion revolves around installing a pressure transducer to measure water volume in a uniquely shaped tank, which is cylindrical with a concave base. The user plans to utilize a TECSIS pressure transducer with a microcontroller to convert pressure readings into volume using the equation P = g * h * density. They face challenges due to the tank's shape, requiring two volume equations: one for the cylindrical part and another for the concave section. The user seeks advice on how to configure the transducer to accurately reflect volume changes for both shapes, emphasizing the need for a method to differentiate between the two volume calculations. The conversation highlights the importance of integrating mathematical principles to achieve accurate volume measurements in complex geometries.
fatima_ib89
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i have to install a pressure transducer to convert the pressure value to volume, but its not the problem, the shape of the water tank , the water tank like cylinder but the base is concave to the bottom, how can i do that ? please
thank you all
 
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A diagram with dimensions would be helpful. Try to solve the problem so we can see where to help.
 
First, thank you for reply
i want to measure the volume of water in the tank by using TECSIS pressure transducer with built in microcontroller and analoge output from it between 4-20mA , by using this equation P=g*h*density, i can get analoge output which indicate the volume, of course after set the microcontroller ,but the shape of the tank like cylinder and concave to the bottom-see the attachment-this means that i have two equation of the volume, what can i use with the transducer to solve this problem?
 

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I would refresh your memory regarding applications of triple integrals in calculus. You have a shape that looks like a hemisphere, you are trying to find its volume bounded by a plane at different heights measured from the bottom of the hemisphere. My "Mathematical handbook of Formulas and Tables" shows the volume of a Spherical cap of Radius r and Height h to be:

V=1/3*pi*h^2(3r-h)

The volume of a Right Circular cylinder of radius r and Height h is:

V=pi*r^2*h

You have two equations for Volume vs height, one for the sphere and another for the cylinder
 
you are extremely right, but for example when the pressure equal 2 bar the output current will be 6 mA,
from this equation P=density*h*g i can get P=density*g*(volume/Pi*r^2) this is for cylinder
so i can set the microcontroller in the transducer to give me indication of volume instead of current
ex:
P= 1000*9.8*(volume/Pi*r^2)....for pure water so the volume = p*(pi*r^2)/1000*9.8
for 1m reduis
volume = p*3.14/1000*9.8...when pressure=2 bar
volume = 64 m^3, and the transdcucer should give me 6mA but i can set the microcontroler
(proportional control) to give me for example 0.64
 
continue...
this is all equation for cylinder, but there is a spherical cap shap as u said , is there any method to switch the transducer and separate the volume indication between this two shapes ..i hope u get it other wise i would have a mistake in my delivery ..thank you
 
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