Quadratic equation, A.P. and G.P. related problem problem

AI Thread Summary
The discussion focuses on a mathematical problem involving quadratic equations where two equations share a common root and the ratios of their coefficients are in arithmetic progression (A.P.). The goal is to prove that the coefficients of the second equation are in geometric progression (G.P.). Participants discuss the properties of A.P. and G.P., emphasizing the use of the mean formula for A.P. and the multiplication property for G.P. The solution involves substituting values into a derived formula to establish the required proof. The problem is successfully resolved, confirming the relationship between the coefficients.
Sumedh
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Homework Statement


if ax2+2bx+c=0 and a1x2+2b1x+c1 have a common root and
a/a1 ,b/b1 ,c/c1 are in A.P.

show that a1,b1,c1 are in G.P.


Homework Equations





The Attempt at a Solution



I know the mean formula of A.P. i.e. the middle term is the mean of the other two.

any hints of which formula of G.P. to use and how to solve?
 
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Sumedh said:

Homework Statement


if ax2+2bx+c=0 and a1x2+2b1x+c1 have a common root and
a/a1 ,b/b1 ,c/c1 are in A.P.

show that a1,b1,c1 are in G.P.


Homework Equations





The Attempt at a Solution



I know the mean formula of A.P. i.e. the middle term is the mean of the other two.

any hints of which formula of G.P. to use and how to solve?

You realize that fro an AP, where each term is obtained by adding a fixed amount, you add the 1st and 3rd and divide by 2 to get the 2nd or middle.
In a GP where terms are obtained by multiplying by a fixed amount, you can multiply the 1st an 3rd then take the second root to get the 2nd or middle term. [second root = square root]
 
thank you i got the answer.

let the AP be
(A-D) , (A), (A+D)

then
a=a1(A-D)
b=b1(A)
c=c1(A+D)
one root is common so
putting these values in the formula
(c1a2-c2a1)2 = (a1b2-a2b1)(b1c2-b2c1)

we get the required proof.


thank you very much:smile:
 
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