Quantum Mechanics: Eigenstates of ##\hat{\mathbb{S}}_x##

In summary, the problem asks to find the eigenstates of ##\hat{\mathbb{S}}_x## for a spin ##-1## particle in terms of the eigenstates ##|1,1\rangle, \ |1,0\rangle,## and ##|1,-1\rangle## of ##\hat{\mathbb{S}}_z##. This can be done by finding the eigenvectors of ##S_x## in the given basis and writing them as linear combinations of the basis vectors. The matrix representation of ##S_x## can then be used to find the eigenvalues and eigenvectors, which can then be transformed into the basis given by ##S_z##.
  • #1
Robben
166
2

Homework Statement



Determine the eigenstates of ##\hat{\mathbb{S}}_x## for a spin##-1## particle in terms of the eigenstates ##|1,1\rangle, \ |1,0\rangle,## and ##|1,-1\rangle## of ##\hat{\mathbb{S}}_z.##

Homework Equations

The Attempt at a Solution



Not sure exactly how to set this problem correctly.

We have for the matrix representation: ##
S_z= \hbar\left[\begin{array}{ c c }1&0& 0 \\0 & 0 &0\\0&0&-1\end{array} \right]## and ##S_x= \frac{\hbar}{\sqrt{2}}\left[\begin{array}{ c c }0&1& 0 \\1 & 0 &1\\0&1&0\end{array} \right].## From this it asks to determine the eigenstates of ##S_x## so do I just find the eigenvalues for ##S_x## and then determine the eigenstates from those? Not sure exactly what is being asked.
 
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  • #2
The state space is a 3-dimensional vector space, so it can be spanned with any three linearly independent vectors. In particular, the three eigenvectors of Sx can span the space, or the three eigenvectors of Sz can span the space. The problem is asking you to find the three eigenvectors of Sx, and then transform those three vectors into the basis given by the three eigenvectors of Sz. Do you know how to transform a vector from one basis to another?
 
  • #3
phyzguy said:
The state space is a 3-dimensional vector space, so it can be spanned with any three linearly independent vectors. In particular, the three eigenvectors of Sx can span the space, or the three eigenvectors of Sz can span the space. The problem is asking you to find the three eigenvectors of Sx, and then transform those three vectors into the basis given by the three eigenvectors of Sz.

So I need to find the eigenvalues of ##S_x##, i.e., the ##S_x## matrix I have above? Once I find the eigenvalues I will then find the eigenvectors?

Do you know how to transform a vector from one basis to another?

Could you elaborate on how I can do that, please?
 
  • #4
What you should understand is that when you write a matrix down for an operator such as you have done for ##S_z## and ## S_x ##, you have already chosen a basis to represent that operator in. In this case the basis you have written it in is ## | 1 -1 \rangle ## , ## | 1 0 \rangle ## and ## | 11 \rangle ## . Can you see this?

The question is asking you to find the eigenvectors of ##S_x## and write it as a linear combination of these vectors.
 
Last edited:
  • #5
Idoubt said:
What you should understand is that when you write a matrix down for an operator such as you have done for ##S_z## and ## S_x ##, you have already chosen a basis to represent that operator in. In this case the basis you have written it in is ## | 1 -1 \rangle ## , ## | 1 0 \rangle ## and ## | 11 \rangle ## . Can you see this?.

I can't see it. Can you elaborate please?
The question is asking you to find the eigenvectors of ##S_x## and write it as a linear combination of these vectors.

In order to find the eigenvectors I must find the eigenvalues. Now from this, what exactly are we writing the eigenvectors as a linear combination of?
 
  • #6
Robben said:
I can't see it. Can you elaborate please?

For example let us take ##S_z## and systematically write down it's representation in the ##\{ |1,-1\rangle, |1,0\rangle, |1,1\rangle \}## basis. First of all we need to know the action of the operator ##S_z## on this basis. Since these states are eigenstates of the ##S_z## operator this is simple to write down as,
## S_z |1,-1\rangle = -\hbar |1 -1\rangle ##
## S_z |1,0\rangle = 0 ##
## S_z |1,1\rangle = \hbar |1 1\rangle ##

Now that we know this we can construct the matrix representation of ##S_z## in this basis by making the following assignements

## |1,1\rangle = \left( \begin{array}{c}
1\\
0 \\
0 \end{array} \right),
|1,0\rangle =
\left( \begin{array}{c}
0\\
1 \\
0 \end{array} \right),
|1,-1\rangle = \left( \begin{array}{c}
0\\
0 \\
1 \end{array} \right)
##
and the matrix representation of the operator is

##S_z = \left( \begin{array}{ccc}
\langle 1,1 | S_z | 1,1 \rangle &\langle 1,1 | S_z |1,0\rangle &\langle 1,1| S_z | 1,-1 \rangle \\
\langle 1,0 | S_z | 1,1 \rangle &\langle 1,0 | S_z |1,0\rangle &\langle 1,0| S_z | 1,-1 \rangle \\
\langle 1,-1 | S_z | 1,1 \rangle &\langle 1,-1 | S_z |1,0\rangle &\langle 1,-1| S_z | 1,-1 \rangle
\end{array} \right)
##

which you can verify is the definition that you have given.
Robben said:
In order to find the eigenvectors I must find the eigenvalues. Now from this, what exactly are we writing the eigenvectors as a linear combination of?

##S_x## is also given in the same basis, so if you find the eigenvectors of ##S_x ## you will get some vector

##
|\phi\rangle = \left( \begin{array}{c}
a\\
b \\
c \end{array} \right) =
a\left( \begin{array}{c}
1\\
0 \\
0 \end{array} \right) +
b\left( \begin{array}{c}
0\\
1 \\
0 \end{array} \right) +
c\left( \begin{array}{c}
0\\
0 \\
1 \end{array} \right)
##
or
##
| \phi \rangle = a|1,1\rangle + b|1,0\rangle + c|1,-1\rangle

##

So essentially you need to find the eigenvectors of the matrix representation of ##S_x## you have given.
 
  • #7
I see now, thanks to your help. Thank you very much!
 

Related to Quantum Mechanics: Eigenstates of ##\hat{\mathbb{S}}_x##

What is an eigenstate in quantum mechanics?

An eigenstate in quantum mechanics is a state in which a physical quantity, such as momentum or spin, has a well-defined value. In other words, the state is an eigenvector of the corresponding operator, and the value of the physical quantity is the corresponding eigenvalue.

What is the significance of the eigenstates of ##\hat{\mathbb{S}}_x##?

The eigenstates of ##\hat{\mathbb{S}}_x## represent the possible outcomes of measuring the spin of a particle in the x-direction. They are important because they provide a complete basis for describing the spin state of a particle in quantum mechanics.

How are eigenstates of ##\hat{\mathbb{S}}_x## related to spin up and spin down states?

The eigenstates of ##\hat{\mathbb{S}}_x## can be thought of as superpositions of spin up and spin down states. The eigenstate with an eigenvalue of +1 represents a spin up state, while the eigenstate with an eigenvalue of -1 represents a spin down state.

What is the physical interpretation of the eigenvalues of ##\hat{\mathbb{S}}_x##?

The eigenvalues of ##\hat{\mathbb{S}}_x## represent the possible values of the spin of a particle in the x-direction. The eigenvalue of +1 corresponds to a particle with spin aligned with the x-axis, while the eigenvalue of -1 corresponds to a particle with spin in the opposite direction.

How do the eigenstates of ##\hat{\mathbb{S}}_x## relate to other quantum mechanical operators?

The eigenstates of ##\hat{\mathbb{S}}_x## can be used as a basis for describing the spin state of a particle in other directions, such as the y- or z-direction. They also have applications in other areas of quantum mechanics, such as in the study of entanglement and quantum information processing.

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