Quantum Mechanics - Matrix representations

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
9 replies · 3K views · last reply
Graham87
Messages
72
Reaction score
16
Homework Statement
See pic
Relevant Equations
See pic
Printed text problem: Matrix representations. Using the basis vectors |j,m> of J^2 and Jz to obtain a matrix representation of the angular momentum operators Jx, Jy, Jz and J^2 for the case of j = 3/2.

I have found J^2 and Jz, but I am not sure how to find Jx and Jy.
I’m thinking maybe use J+-=Jx+-iJy ? But I get unclear results.

Handwritten working on graph paper: j = 3/2 with m = -3/2, -1/2, 1/2, 3/2; Jz|j,m> = ħm|j,m> shown as a diagonal 4x4 matrix with entries 3/2, 1/2, -1/2, -3/2 times ħ; J²|j,m> = j(j+1)ħ²|j,m> = (1.5ħ²/4) times a 4x4 identity matrix.


Thanks!
 
Physics news on Phys.org
Graham87 said:
Homework Statement:: See pic
Relevant Equations:: See pic

View attachment 313615
I have found J^2 and Jz, but I am not sure how to find Jx and Jy.
I’m thinking maybe use J+-=Jx+-iJy ? But I get unclear results.

View attachment 313617

Thanks!
Using ##J_{\pm}## sounds like a good idea. Show us what you get.
 
  • Like
Likes   Reactions: Graham87
Graham87 said:
I’m thinking maybe use J+-=Jx+-iJy ? But I get unclear results.
You have to do it the other way around: Express ##J_x## and ##J_y## in terms of ##J_+## and ##J_-##.
 
  • Like
Likes   Reactions: Graham87
Handwritten derivation on grid paper: J+ − J− = (Jx + iJy) − (Jx − iJy), giving Jy = (1/2i)(J+ − J−); and J+ + J− = 2Jx, giving Jx = (1/2)(J+ + J−).

I got this, but it gets messy when I try to find J+- with this expression:
Handwritten equation on grid paper: J± |j, m⟩ = ħ√((j ∓ m)(j ± m + 1)) |j, m±1⟩, the ladder-operator action on angular momentum states.

I don’t know how to form the matrix, what goes where.
 
Matrix elements are found using ##\braket{j',m' | J_x | j, m}##, so you can start by calculating ##J_+ \ket{j,m}## and ##J_- \ket{j,m}## explicitly for the 4 ##\ket{j,m}## states you need to consider here.
 
  • Like
Likes   Reactions: Graham87
Something like this?

Handwritten notes on squared paper: basis column vectors e1 to e4 for spin 3/2 states, formulas for J+ and J- matrix elements, inner product calculations, and the 4x4 matrix representations of J+ and J-.

Handwritten matrix representations on grid paper: Jx = (h/2) times a 4x4 matrix with zeros on the diagonal and entries sqrt(2), sqrt(6), sqrt(6), sqrt(2) above and below; and Jy = (1/2i) times a 4x4 matrix with the same pattern of square-root entries.
 
  • Like
Likes   Reactions: PeroK
Good effort, but I don't agree with some of the entries in the ##J_{\pm}## matrices.
 
  • Like
Likes   Reactions: Graham87
Here's a tip. A lot of physics textbooks write one formula with various ##\pm## and ##\mp##. I find it easier to keep the formulas separate with either ##+## or ##-##.
 
  • Like
Likes   Reactions: Graham87
Graham87 said:
Where in the matrix did you not agree ?
The non-zero entries!
 
  • Like
Likes   Reactions: Graham87
PeroK said:
The non-zero entries!
Thanks! Just noticed my error.
cheers!