Quantum Mechanics particle in Box Normalization

Bahadar
Messages
4
Reaction score
0

Homework Statement



A particle confined to a cubic box of dimension L the
wavefunction normalization factor is (2/L)^3/2 , the same value for all stationary
states. How is this result changed if the box has edge lengths L1, L2, L3, all of
which are different.


Homework Equations



Normalization condition: 1=∫∫∫P(r)dxdydz


The Attempt at a Solution



I know how the normalization for a cubic box has been determined but I am confused how it should be calculated for a box of unequal sides.
 
Physics news on Phys.org
Of course you're confused. The point of the problem is for you to figure it out.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top