Quantum Numbers for a couple of electrons Help needed

AI Thread Summary
The discussion focuses on determining the quantum numbers (QNs) for electrons in the configurations 4p^2 and 6s^2. For 4p^2, the correct quantum numbers are n=4, l=1, m=-1 and 0, with spins of +1/2 for both electrons. For 6s^2, the quantum numbers are n=6, l=0, m=0, and spins of +1/2. There was some confusion regarding the filling of orbitals in the p subshell, but it was clarified that both electrons in 4p^2 can have positive spins. The conversation emphasizes the proper assignment of quantum numbers based on electron configurations.
mathzeroh
Messages
98
Reaction score
0
Good evening scholars! i just had a couple of questions about QNs.

ok so the problem says:

Give the sets of {n, l, m, s} for the electrons in:
a) 4p^2
b) 6s^2

i just want to see if I'm on the right track. here's what i put for the first one (a):

n= 4
l= 1
m= -1, 0
s= +/- 1/2

thanks!
 
Physics news on Phys.org
Keep in mind that m is from -L TO +L
m would be -1, 0 , and +1
your spin is fine

what about the 6s^2
so obvious n =6,
p = ?? for the s shell waht is the P value?
and thus what is the m value and s values correspondingly?
 
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-
 
mathzeroh said:
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-

WHOOPS SORRY

my mistake, for the 4p2 you are correct the p orbital would be filled up for the -1 and 0 part
however, since you fill in teh positive spins in first both the electrons have positive spin
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top