A Quantum Optics - transition from pure to mixed state

SchroedingersLion
Messages
211
Reaction score
56
Hello guys,

I am trying to understand the following experiment:

1. Prepare a 2 level atom in state |0>
2. Shine in a Pi/2 pulse --> atom goes to 1/√2 (|0>+|1>)
3. Wait time T
4. Shine in second Pi/2 pulse
a) if the state is pure: atom will go to state |1>, p1=1
b) if the state is mixed: p1=1/2, p2=1/2

And below a plot of p1 with respect to T. It starts at p1=1 and decreases with T to 1/2.

I don't understand point 4.
What I understand:
If T=0, the state is a pure superposition and gets to |1> via the second Pi/2 pulse
But as soon as time T passes after the first pulse, I am losing information, since the atom interacts with the vacuum fields (who are also responsible for spontaneous emission).

But what does that mean? Does the interaction with the vacuum 'destroy' my superposition and force the atom into either state |0> or state |1>?
Because if I then apply my second light pulse, it would go either from |0> to 1/√2 (|0>+|1>) or from |1> to 1/√2 (|0>+|1>), and then I would have my probabilities at 1/2.

Regards
 
Physics news on Phys.org
SchroedingersLion said:
But as soon as time T passes after the first pulse, I am losing information, since the atom interacts with the vacuum fields (who are also responsible for spontaneous emission).
Yes, but you also have to consider the lifetime of the state with respect to the duration of the experiment. Using a long-lifetime excited state, one can neglect any effect due to spontaneous emission. It can also become simply a source of uncertainty (for instance, in an atomic clock).
 
Ok, let's assume it has a short enough average lifetime to play a role.
How exactly is the vacuum field 'destroying' the superposition? Is it possible to understand it intuitively?
 
The vacuum is not a field but a specific state of quantum fields.
 
SchroedingersLion said:
I am trying to understand the following experiment:

1. Prepare a 2 level atom in state |0>
2. Shine in a Pi/2 pulse --> atom goes to 1/√2 (|0>+|1>)
3. Wait time T
4. Shine in second Pi/2 pulse
a) if the state is pure: atom will go to state |1>, p1=1
b) if the state is mixed: p1=1/2, p2=1/2

I am not sure whether the interpretation is correct. Do you have a reference where the experiment is described?
 
  • Like
Likes jim mcnamara
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Replies
6
Views
2K
Replies
16
Views
2K
Replies
35
Views
3K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
65
Views
9K
Back
Top