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Quantum Physics - Electron in a 1d Potential Well Question

  1. Aug 7, 2014 #1
    1. The problem statement, all variables and given/known data

    This is a Quantum Physics problem.

    An electron moves in a one-dimensional potential well such that the potential V = 0 for |x| ≤ a, and V = ∞ otherwise.

    The system has energy eigenfunctions:

    Un = a^(-1/2) cos (n∏x/2a), for n odd, and
    Un = a^(-1/2) sin (n∏x/2a) for n even.

    (Those are both for |x| ≤ a)

    and Un = 0 for |x| > a.

    The lowest energy level of the system is 37.6 eV.

    At t=0, the wavefunction for the system is

    ψ(x, t = 0) = a^(-1/2) (2 cos (∏x/2a) + sin (∏x/a)).

    (1) Write the wavefunction as a linear combination of energy eigenfunctions, and hence normalise the wavefunction.

    (2) What are the possible results of a measurement of electron energy?


    2. Relevant equations

    Not really sure!

    3. The attempt at a solution

    Okay, so I think I have 1) complete. The wavefunction as a linear combination of energy eigenfunctions is ψ = 2u1 + u2.

    Also, I normalised it and got ψ (norm) = ψ/√5. I'm pretty sure I understand all this.

    My problem is with (2). I know that the possible results of an energy measurement are either u1 or u2.

    And u1 = E1 = 37.6 eV (given in question)
    But I don't understand how to get E2. Apparently E2 = 4 (E1)?? Why would that be true.. I don't understand where that 4 came from? :/

    Sorry, I'm an absolute beginner to Quantum Physics so I'm going very very slowly!

    Any help would be appreciated :)
     
  2. jcsd
  3. Aug 7, 2014 #2

    Simon Bridge

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    ... you should have this already in your notes when you covered the infinite square well in general. If not, then you'll have to put U2 through the Schrodinger equation to find the eigenvalue. (H-E2)U2=0.

    The possible outcomes of a measurement are the eigenvalues, not the wavefunctions. Important not to mix them up. It is never correct to write "u1=E1" for example.
     
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