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S.Daedalus said:OK, there's a bit I don't get, I think. So the final state is:
##|final\rangle = \frac{1}{\sqrt{3}} |\overline{h}\rangle |-\frac{1}{2}\rangle + \frac{1}{\sqrt{3}} |\overline{t}\rangle |\frac{1}{2}\rangle + \frac{1}{\sqrt{3}} |\overline{t}\rangle |-\frac{1}{2}\rangle##
Expressed in the ok/fail-basis of ##\overline{W}##, this is:
##|final\rangle = \frac{2}{\sqrt{6}}|\overline{fail}\rangle|-\frac{1}{2}\rangle + \frac{1}{\sqrt{6}}|\overline{fail}\rangle|\frac{1}{2}\rangle - \frac{1}{\sqrt{6}}|\overline{ok}\rangle|\frac{1}{2}\rangle##
After ##\overline{W}## measures and obtains the ##\overline{ok}##-outcome, only the term ##|\overline{ok}\rangle|\frac{1}{2}\rangle## survives. If we express that again in the ##\{|\overline{h}\rangle,|\overline{t}\rangle\}##-basis, we get:
##|\overline{w}=\overline{ok}\rangle=\frac{1}{\sqrt{2}}(|\overline{h}\rangle|\frac{1}{2}\rangle - |\overline{t}\rangle|\frac{1}{2}\rangle)##
But this is not a state in which we can claim that ##\overline{F}## predicts that W observes 'fail', as either outcome is possible. Consequently, if ##\overline{F}## applies quantum mechanics to themselves, they should rather reason that if ##\overline{W}## applies their measurement and observes the ##\overline{ok}##-outcome, then either measurement outcome of W's measurement is possible, so no contradiction arises. Alternatively, ##\overline{W}## is wrong to believe that their inference from the measurement outcome still holds after the measurement has been performed, since that inference depends on the structure of the pre-measurement state.
The only way of making this seem reasonable, it looks to me, is if ##\overline{F}## supposes that their measurement (of the coin) 'collapses' the state to 'tails'; but that's just the same as the original Wigner's Friend-thought experiment, where if the friend were to make that assumption, they'd predict (wrongly) that a suitable experiment involving the entire lab would show no interference. So if F supposes that W observes 'fail', that just seems to me to be a misapplication of quantum mechanics in the same way as Wigner's Friend's prediction of no interference would be.
I think you're right. The paradox just boils down to: noncommuting operators can't all be said to have definite values at the same time.
But as I summarized in one of the earlier posts:
- ##\overline{W}## can conclude: "If I measure ##\overline{ok}##, then ##F## must measure ##+1/2##.
- ##F## can conclude: "If I measure ##+1/2##, then that implies that ##\overline{F}## measured ##\overline{t}##"
- ##\overline{F}## can conclude: "If I measure ##\overline{t}##, then ##W## will measure ##fail##"