Quaternions And Complex Numbers

Kambiz_Veshgini
Messages
2
Reaction score
0
1.
Are the HAMILTON‘ian unit vectors i, j, k still valid beside the imaginary
unit i(Sqrt(-1))?
Can we expand quaternions using complex numbers?

2.
Is the quaternion a+bi+0j+0k equal to the complex number a+bi ?
 
Mathematics news on Phys.org
1. what does valid mean. yes the quarternions can be realized as en extension of the complex numbers, though as i doesn't commute with j or k, there are several ways of doing this and different sources may adopt different ways.

3. Yes and no. a+bi+0j+0k=a+bi IN the quartenions.
 
Hi Kambiz,
one picture/representation of quaternions (i,j,k)
you can have is of them being traceless hermitian 2*2 matrices
over complex numbers.

(Then exponentiating combinations of them, you generate 2*2 unitary matrices, which we can map to ordinary rotations in 3 dimensions - in fact, I believe, it was Hamilton's obsession with `adding rotations' (in the manner that one might add vectors so effortlessly) that led him to write down the quaternionic algebra in the first place.)

A common basis for this 2*2 complex matrix representation of
quaternions is given by the Pauli matrices, used extensively in physics!

This is the lowest dimension representation of the quaternionic
algebra [sometimes called the spinor representation].

best, Anton.
 
Last edited:
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top