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Well, it's easier to integrate the following:Red_CCF said:I was able to get the x(t) equation but unable to get the form for the work equation. For the work equation, are we solving:
-W=\int{C(\frac{dx}{dt})^2dt}+\int{kx\frac{dx}{dt}dt}
where we integrate t from 0 to infinity? If so I probably made some arithmatic errors during expanding/simplification.
-W=A\int_0^∞{P_{ext}(t)\frac{dx}{dt}dt}
You can get additional simplification by integrating by parts:
P_{ext}(t)\frac{dx}{dt}dt=d(xP_{ext})-x\frac{dP_{ext}}{dt}dt
Ooops. You're right. I'm missing a factor of A. Thanks.With regards to the work equation, is the area A supposed to be squared?
In Post #146, I discussed the fact that the "effective" amount of time to complete a single discrete step is C/k. Please read over my post carefully. If you wait until t = 4C/k, the displacement will be 98% of the displacement you get at infinite time. It won't matter significantly if you start the next discrete step then, or wait an infinite amount of time. So the nominal time for a sequence of n discrete steps will be nC/k (or 4nC/k if you prefer).In discrete step, we integrated each step from t = 0 to infinity, essentially saying that each step takes infinite time. As we take the number of steps n to approach infinity, are we basically saying that the process will take ∞2 to complete?
τ is a constant we are using to parameterize how fast we vary the external pressure. A small value of τ means we are varying it very rapidly, and a large value of τ means we are varying it slowly. Physically, τ is the amount of time it takes for Pext to rise 63% of the way from PEi to PEf.What is τ physically?
As I said in several previous posts, we can control the applied external pressure variation Pext(t) to be any function of time we desire.I see that it is synonymous with the number of steps (when pressure is increased in discrete steps), but how does one measure/control this variable?
Chet
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