Question about Full scale deflection

AI Thread Summary
To measure a 120-volt circuit with a 30-volt voltmeter, a resistor must be placed in series to drop the excess voltage. The voltmeter's sensitivity indicates it has a resistance of 30 kOhms at full scale. The calculation involves determining the additional resistance needed to ensure only 30 volts are measured, which requires understanding Ohm's Law. Proper unit usage is crucial to avoid errors in calculations. The discussion emphasizes the importance of systematic problem-solving steps to arrive at the correct resistor value.
Tony Meloni
Messages
6
Reaction score
0

Homework Statement


hello, just came across this type of question for first time.
A voltmeter with a range of 0-30volts is to be used to measure a 120 volt circuit. calculate the value of the resistor to be placed in series with the meter. the sensitivity of the meter is 1000 ohms per volt ?

Homework Equations



im taking a guess its 120-30 = 90 vd x 1000 = 90k ohms ? any input would help thanks

The Attempt at a Solution

 
Physics news on Phys.org
Don't guess. What does the sensitivity tell you about the resistance at 30 V at the voltmeter?
 
its telling me at 30volts its 30k ohms since its 1k per volt ..needs 90volts to drop across the resistor .. 120volt x 1000 k = 120k - 30k = 90k x .001ma = 90vd ?
 
Last edited:
Tony Meloni said:
120volt x 1000 k
What do you multiply here and what are the units? k without a unit doesn't have a proper meaning.
Tony Meloni said:
120volt x 1000 k = 120k - 30k
That equation is wrong.
Tony Meloni said:
120k - 30k = 90k x .001ma
That equation is wrong as well.
Tony Meloni said:
90k x .001ma = 90vd
That equation has at least an issue with units.
 
so what are the proper steps to find the answer ?
 
If the voltmeter has 30 kOhm, what is the maximal current flowing through it?

At this current, what do you need as additional resistance to get 90 V voltage drop there?
 
my choices to pick from the homework are

60k ohms 90k ohms

90ohms 150k ohms

if you take 90k x .001 you get 90vd
 
Tony Meloni said:
if you take 90k x .001 you get 90vd
With the right units this can be useful.

Work with units. It helps spotting most errors you'll make if you don't work with them.
 
what do you mean by units ?
 
  • #10
Ohm, Volt, Ampere and so on.
 
  • #11
how would you write out the problem using ohms law ?
 
  • #12
That's your homework task. You need a few simple steps in a row, going from the voltmeter to the additional resistor step by step.
 
Back
Top