Question about power and output power.

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Homework Help Overview

The discussion revolves around measuring output power in the context of pushing a car and running up stairs. Participants explore the factors influencing power output and the relationship between power, mass, and height in these scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss methods for measuring output power, including calculating rolling resistance and maximum speed. Questions are raised about the consistency of power output when changing the number of stairs and the various factors that affect power output, such as mass and fitness level.

Discussion Status

The discussion is ongoing, with some participants providing mathematical approaches and considerations for measuring power. There is an emphasis on showing work and progress before receiving further assistance, indicating a collaborative effort to explore the problem.

Contextual Notes

Participants are encouraged to clarify which specific question they are addressing, and there is mention of assumptions regarding conditions such as road level and tire pressure. The discussion also touches on the variability of power output based on individual characteristics.

vegetables102
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1. How could you measure your output power developed while pushing a car?


2. If you developed a certain amount of power running up let's say 2 flights of stairs, could you develop the same power if you ran up twice as many stairs?


3. What factors affect a persons output power running up stairs?
 
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1.
Rough guess :
Level road assumed, tyres at recommended pressure.

m = mass of the car in kg
g = local gravity rate ( use 9.81 (m/s)/s )
Crr = tyre on ashphalt rolling resistance co-efficient ( use 0.03 )

Rolling resistance force (f) ( constant, regardless of speed ) = m * g * Crr
( answer is in Newtons )

Find the maximum speed (v) you can push the car in metres per second
(mph * 0.44704 = metres per second)

Then :
The power provided (W) to push the car :
W = f * v
(answer is in Watts, divide by 745.7 to get horsepower)

Example :
v = maximum push speed = 4 m/s (example)
m = 1,500 kg
g = 9.81 (m/s)/s
Crr = 0.03

f = m * g * Crr
f = 1,500 * 9.81 * 0.03
f = 441.45 Newtons

W = f * v
W = 441.45 * 4
W = 1,765.8 Watts ( about 2.37 hp )

2.
Energy change (Joules) = m * g * h
m = your mass in kg
g = local gravity rate (use 9.81 (m/s)/s)
h = vertical height moved in metres (floor to floor difference)
Then :
Average Power = energy change / time in seconds
3.
Power output is roughly proportional to your size, but includes factors like sex, fitness level, nutrition etc.
 
Hello vegie, and welcome to PF.

You show us the questions that were put to you. Which question are you putting to PF ?

Anyway, for # 1 I would use a scale between my hands and the car to have guess for the force. Push a certain distance in a certain time and there you are !

(How many tyres does Dean's car have? And does he really think he can push hard enough to get a meaningful furlongs/fortnight -- oh, sorry, mph -- reading from the speedometer ?)

Share your work, Veggie !
 

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