Question about the Archimedes principle and gravity.

AI Thread Summary
Objects on Earth experience buoyancy due to the atmosphere, making them effectively lighter compared to a similar planet with no atmosphere, although their mass remains unchanged. The concept of weight can vary based on the surrounding fluid, as demonstrated by the example of weighing an object in water versus air. While air does exert a buoyant force, the real-world differences in weight due to this effect are minimal and generally not significant for engineering applications. Civil engineers typically do not need to account for atmospheric buoyancy in structural designs unless specifically exploiting this effect. For precise measurements, using a vacuum chamber can eliminate the influence of air pressure on weight.
DrSmersh
Messages
6
Reaction score
0
Hello, I was taking a shower and started to think about balloons and helium and this question came to me:
Wouldn't the things on Earth be lighter than say, a similar planet (same gravity) but with no atmosphere? (because of the push from air)
I googled it but I am not sure of using the correct keywords.
PS: I am starting engineering and my physics knowledge is not very superior to an AP level (I don't really know how to compare our educational systems sorry :P)
 
Physics news on Phys.org
That depends on exactly what you mean by weight. They will have the same mass, and experience the exact same amount of force downward, but without a fluid surrounding them the effect of buoyancy will not exist.

Consider this. If I put a scale at the bottom of a pool, you will weigh less inside the pool than outside according to the scale. However if I put both you and the pool onto a scale, your full weight will show.
 
Drakkith said:
That depends on exactly what you mean by weight. They will have the same mass, and experience the exact same amount of force downward, but without a fluid surrounding them the effect of buoyancy will not exist.

Consider this. If I put a scale at the bottom of a pool, you will weigh less inside the pool than outside according to the scale. However if I put both you and the pool onto a scale, your full weight will show.
Thanks for the reply
Considering that air pushes a baloon I assume that it is a fluid, I mean it has the bouyancy effect on everything in the atmosphere. We might not float but we weight less (like a rock under water) if we compare us standing on a scale in a similar planet (equal gravity), is that correct?
So in all the exercises that i did when practicing Newton's laws the result in real life should be different partialy because of this airpush? I suppose the difference would be very small then, but does a civil engineer have to take that in account when building a bridge or any structure for example? Or a phyisist when trying to measure the as close to real as possible mass of a particle or element (I don't know how they measure this things but suposing that in some part of the process they have to weight something and decompose the forces that are presented)?
 
Last edited:
Mass is measured differently, so we don't really have to worry about that. Plus, if you REALLY want to measure the weight of an object, just take it into a vacuum chamber. In any case, the real world differences are so tiny that in practically all cases you don't need to take them into account in order to build anything. (Unless you are trying to exploit the effect of course)
 
Drakkith said:
Mass is measured differently, so we don't really have to worry about that. Plus, if you REALLY want to measure the weight of an object, just take it into a vacuum chamber. In any case, the real world differences are so tiny that in practically all cases you don't need to take them into account in order to build anything. (Unless you are trying to exploit the effect of course)

Awesome thanks, that answers my question.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
I don't need cloth simulation. I need to simulate clothing meshes. Made of triangles and I need an answer that someone with High School math can understand. I am actually using the time it takes for someone to answer to create a model with less geometry than the one I have been using. I want clothing that can be removed on a model that will be animated. I don't need stretching or wrinkles on my meshes, I just need gravity. I have an idea of how I could do it, but I don't know how to apply...
Back
Top