- #36
gracy
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What are these pictures about?
I don't think so. If Q1 is greater, then only Vxf>Vyf. You can see it here.gracy said:And even if Q1 isn't greater final potential at x will still be greater than final potential at y. Right?
See #37. The polarity of 10uF has changed. If Q1 is more, it will retain its polarity.gracy said:##q_{1f}## + ##q_{2f}## =##Q_{1f}## - ##Q_{2f}##
If ##Q_{1f}## < ##Q_{2f}##
It means ##q_{1f}## < ##q_{2f}##
But it does not tell much about polarity of ##q_{1f}##.
cnh1995 said:eater, Vxf>Vyf. In #37, Q1(charge on 10uF)is less than Q2(charge on 5uF). Hence, polarity of C1(10uF) changed, making Vxf<Vyf.
If Q1<Q2, Vxy will be negative i.e Vx<Vy.gracy said:There will be potential difference between points x and y given by (Q1−Q2)/(C1+C2)
It is a simulation result. It is an example of the case 3 in that video. In that circuit, Q1(charge on 10uF) is less than Q2(charge on 5uF) but initially Vx>Vy. When the middle switch is closed, it becomes the case 3. You can see the polarity of the 10uF reversed in the steady state, making Vx<Vy.gracy said:I am unable to comprehend those pictures in post #37.
It is an android app on my phone.gracy said:Can you give me link to that simulation site?
I thought it was clear to you as to why Vx > Vy . ##\ ## After all, Vx − Vy = (Q1 − Q2)/(C1 + C2) .gracy said:There will be potential different between points x and y given by ##\frac{Q1-Q2}{C1+C2}##
Right?
They are the very same thing in this case.gracy said:I thought this formula is for potential difference and it is not particularly ##V_x## - ##V_y## rather ##V_+## - ##V_-##. I know it's bit odd but that's what I thought.
First, think.gracy said:When I thought it is ##V_+## - ##V_-##
By ##V_+## I mean potential at either x or y whichever is at greater (positive potential ).
(##Q_1## - ##Q_2##)/(##C_1## + ##C_2## )This formula just gives potential difference and does not specify anything about which point is at greater potential.This is what thought.
I wrote there will be potential different between points x and y given by (##Q_1## - ##Q_2##)/(##C_1## + ##C_2## ) because at that time I knew x is at greater potential.
The battery is the source of electrical energy, while voltage is the measure of the potential difference between two points in a circuit. The battery's voltage determines how much energy it can provide to the circuit.
The voltage of a battery directly affects the performance of a device. A higher voltage can make a device run faster or provide more power, while a lower voltage can cause it to run slower or not work at all.
Yes, the voltage of a battery can change over time. As a battery is used, its voltage will decrease until it eventually runs out of energy. Additionally, factors such as temperature and age can also affect the voltage of a battery.
Different types of batteries can have different voltages. For example, a standard AA battery typically has a voltage of 1.5 volts, while a car battery can have a voltage of 12 volts. The materials and design of the battery determine its voltage.
Voltage and current are two different properties of electricity. Voltage is the measure of potential difference between two points, while current is the measure of the flow of electric charge. In other words, voltage is like the pressure that pushes the electricity through a circuit, while current is the amount of electricity flowing through the circuit.