Question dealing with electromagnetic induction

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To calculate the induced emf in the automobile's antenna, the relationship E = -Blv must be adapted since the velocity and magnetic field are not perpendicular. The Earth's magnetic field is at an angle of 65 degrees, which requires using the component of the magnetic field that is perpendicular to the direction of motion. The effective magnetic field can be calculated using B_perpendicular = B * sin(θ), where θ is the angle between the magnetic field and the direction of motion. The induced emf can then be determined by substituting this effective magnetic field into the original equation. Understanding the geometry of the situation is crucial for accurately calculating the induced emf.
DSUND34
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Question:
An automobile has a vertical radio antenna 1.2m long. The automobile travels at 65.0 km/h on a horizontal road where the Earth's magnetic field is 50.0 mT directed toward the north and downward at an angle of 65.0 degrees below horizontal.

calculate the magnitude of the induced emf.

I know that when a conducting bar of length l moves through a magnetic field B with a velocity of v so that v is perpendicular to B the emf is induced in the bar (called a motional emf)

E = -Blv

I'm stumped because this law only applies when the velocity and the magnetic field are perpendicular, and in this problem they are not. If anyone can explain this that would be awesome.
 
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The equation you have is a simplified one in that it assumes that they are perpendicular. So, what do we know about things that are perpendicular? This equation implies that when they are perpendicular, the voltage is at its maximum. When thinking about perpendicular and maximum, what comes to mind?
 

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