- #1

paytona

- 11

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## Homework Statement

A 425 mA conventional current is induced in a 48.0cm wire moved through a magnetic field. A 11.5 Ω resistor is connected to the wire as shown in the diagram below. If the magnetic force acting on the wire is 323 mN, then determine the direction and magnitude of the velocity of the wire moving through the magnetic field.

(Diagram is attached to this thread)

## Homework Equations

B=F/IL

EMF=BlvsinΘ

V=IR

## The Attempt at a Solution

My first step was to solve for the magnetic flux using B=F/IL

B= 323x10^-3 / (0.425A)(0.48m)

B= 1.5833333T

For my second step I found the Voltage of the current and resistor using V=IR

V=(0.425A)(11.5Ω)

V=4.8875V

For my third step I used V=Blv to solve for velocity

4.8875/[(1.583333T)(0.48m)= v

6.430934591m/s = v

and then I plugged it in to the formula EMF=Blvsinθ

EMF=(1.58333)(0.48)(6.430934591)(sin90°)

EMF= 4.8875V

I know this is mostly wrong but I didn't know any other way to attempt this.

Please help!