Question on expansion and Compression of gas?

AI Thread Summary
The discussion revolves around the thermodynamic processes involving gas expansion and compression under isothermal conditions. When the gas pressure is suddenly reduced, it expands to a new equilibrium volume calculated using Boyle's Law, with the change in internal energy (ΔU) being zero. The work done during this expansion can be expressed as q = -p*ΔV, indicating that heat is absorbed from the surroundings. When the pressure is increased back to its initial state, the internal energy remains unchanged, and the same equations apply for the work done and heat exchange. The poster seeks confirmation on their calculations and understanding of the processes involved.
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Homework Statement



If a pressure of gas is suddenly reduced and we let the gas to expand again until it reaches equilibrium. What is final volume, work done and heat in this process? and what would be change in internal energy?
Again the pressure is suddenly increased back to initial pressure and gas is compressed to initial volume. What would be work done heat and change in internal energy?
Temperature is same throughout all process

Homework Equations



PV=nRT
ΔU=q+w
w=p*ΔV

The Attempt at a Solution



Here All the process is done at isothermal condition so Boyles law apply
P1V1=P2V2

where V2 is volume after the gas comes to equilibrium, so,
V2=P1V1/P2

since the process is carried in isothermal condition
ΔU=0

w=p*ΔV

0=q+p*ΔV -------> q=-p*ΔV

Now when the pressure is increased back to initial condition

ΔU=0 ( since process is still isothermal)
ΔU=q+p*ΔV ---------> q=-p*ΔV, here change in volume is volume after decreasing pressure - initial volume

I am not sure if I am correct or not? Help
 
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