Question on gravitation and rotation of the Earth

AI Thread Summary
The discussion revolves around a physics problem involving a spring balance on a ship sailing at the equator. Participants analyze how the scale reading changes when the ship is in motion compared to when it is at rest, focusing on the effects of the Earth's rotation and the ship's speed. The equations governing the tensions in the spring balance are derived, leading to confusion over the correct form of the answer. Clarifications are provided regarding the need to express the final answer as a multiple of the initial scale reading, and the role of gravitational force in the calculations is discussed. Ultimately, the original poster successfully arrives at the correct answer after addressing the concerns raised.
AakashPandita
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Homework Statement


A body is suspended on a spring balance in a ship sailing along the equator with a speed ## v' ## . If ## \omega ## is the angular speed of the Earth and ## \omega_0 ## is the scale reading when the ship is at rest , the scale reading when the ship is sailing, will be very close to
(a) ## \omega_0 ##
(b) ## (\omega_0)(1 + \frac { 2 \omega v'}{g}) ##
(c) ## (\omega_0)(1 \mp \frac { 2 \omega v'}{g}) ##
(d)none of these

Homework Equations


Let mass of object be m
Radius of Earth be R.
Tension in spring balance=Reading in spring balance = ## \omega_0 ##
Tension be T when ship not sailing and Tension be T' when ship is sailing

When ship is not sailing
## mg - T = m (\omega)^2 R ##
When ship is sailing
## mg - T' = m (\omega \mp v'/R)^2 R ##
I solved for T' but the answer is not coming.
I could show the working but latex is hard to write.
 
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AakashPandita said:
I could show the working but latex is hard to write.
But if you don't post your working nobody can tell where you are going wrong.
 
IMG_20150501_033610.jpg
 

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That's fine so far, but notice that in the answers everything is expressed as a multiple of ##\omega_0##. Get your answer into that form. (You will probably also need to discard some third order term.)
 
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Wait a minute. Doesn't the value of g that we use account for the centripetal force due to rotation of earth? Is ## g- (\omega)^2 R =g ## using approximation? If yes then how?
 
I got the answer. Thanks a lot.
 
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