Question on quarter wave circuit?

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A quarter wave circuit can indeed have an LC configuration that resonates at a specific frequency while maintaining a quarter wavelength. In this case, a series LC circuit with a 500uH inductor and a 10pF capacitor resonates at 2.25MHz. If the inductor acts as a shorted transmission line of 1/4 wavelength, it behaves as an open circuit, while a length of 1/8 wavelength would yield an inductive reactance equal to its characteristic impedance. The circuit will exhibit high voltages across the inductor and capacitor when driven by a low resistance generator. Current flow in this series resonant circuit is primarily determined by the generator due to the circuit's near-zero resistance.
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Hi all, first post here.

I am studying 1/4 wave circuits and I've been wondering.

Can you have a LC circuit in which the reactances of the L and C produce resonance, while at the same time having the circuit be a 1/4 wavelength?

If so what would this circuits characteristics be?
 
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BHY-BK said:
Hi all, first post here.

I am studying 1/4 wave circuits and I've been wondering.

Can you have a LC circuit in which the reactances of the L and C produce resonance, while at the same time having the circuit be a 1/4 wavelength?

If so what would this circuits characteristics be?
Welcome to the PF.

Can you post the Relevant Equations? Please show what you have been studying, and show the part that you are wondering about... :smile:
 
OK,

You have a series LC circuit. The L value is 500uH while the C value is 10pF. So the resonant frequency is 2.25MHz. Now, let's say the electrical length of the inductor is exactly 1/4 wavelength at 2.25MHz. How would this circuit behave when driven at it's resonant frequency (2.25MHz) by an AC source?
 
BHY-BK said:
OK,
I presume that the inductor is actually a piece of shorted transmission line having a length of 1/4 wavelength at 2.25 MHz. In such case it will behave as an open circuit and cannot look like 500uH.
If, however, the length of wire in the inductor is about 1/4 wavelength and the inductor looks like a shorted line 1/8 wavelength long, then it will have an inductive reactance numerically equal to its characteristic impedance. In this case the circuit appears the same as the LC series series circuit over a fairly wide range of frequencies centred on the resonant frequency.
500uH has a reactance of 707 ohms at 2.25 MHz, so the line would require a Z0 of 707 ohms.
If the circuit is driven by a low resistance generator in series with it, high voltages will appear across L and C.
 
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Tech99

Thanks for the explanation, It is appreciated.

What about the current? How would you determine current flow in this circuit?
 
What about the current? How would you determine current flow in this circuit?
A series resonant circuit has a resistance near zero, so the current will be mainly decided by the generator.
 
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