A block weighing 300 N slides downwards on the angled surface shown at an initial velocity of 2.5 m/s. At t = 0, a force P with the given orientation is applied until the block stops. Knowing that it took 5 seconds for the block to stop and that the coefficient of kinetic friction μk = 0.1, determine the magnitude of P
F = Fn x coefficient of friction s/k
The Attempt at a Solution
First i broke the forces into components. Added the Fn and Friction force on the diagram and labelled 300N force acting downwards. Once i broke the forces into components i got two equations, one for forces acting on the y-axis and the second for forces acting on the x-axis.
-0.4226P + Fn - 281.90 = 0 ---------- Equation (1)
0.9063P - F(f) +102.606 = 0 ---------- Equation (2) Note that F(f) is force of friction.
Then i knew that F(f) = Fn x 0.1 from the question so i replaced it F(f) with it.
-0.4226P + Fn - 281.90 = 0
0.9063P - 0.1Fn +102.606 = 0
After this i solved these two equations simultaneously and found the value of P.
My question/confusion is regarding all the other information given in the question, such as the initial velocity, time etc. I feel like i have done something wrong here. Any guidance would be highly appreciated.[/B]