Question Regarding Velocity-Time Graphs

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Homework Statement



The figure below shows the velocity-time graph of a train that starts from the origin at t = 0s

Hand-drawn velocity-time graph with v on the vertical axis (-1, 0, 1, 2) and t(s) on the horizontal axis (2, 4, 6, 8, 10). The line rises from -1 at t=0 through 0 at t=2 to 2 at t=4, then stays flat at 2 until t=10.


a) Draw a position-time graph and an acceleration-time graph for the train

b) Find the acceleration of the train at t = 3.0 s

Homework Equations



a = Vf - Vi / t

x = 1/2 at^2 + Vi x t + Xi


The Attempt at a Solution



a)
Two hand-drawn graphs: left, x against t with a V-shaped dip to about -3 at t = 2 then a straight line rising through zero at t = 4; right, a step-shaped acceleration against t graph with a red line at 1.0 for t below 4 and a red line at 0 after t = 4.


b) 1 m/s^2

Do my answers look right? If not, what did I do wrong?
 
The acceleration is correct, and the graph of x(t) is almost correct, only the part between 0 and 4 s does not look parabolic, and check x at t=2 s. ehild
 
Looks right to me. But those are really, really, truly, bad graphs.