Archived Quick circuit help/confirmation

  • Thread starter Thread starter RyanSchw
  • Start date Start date
  • Tags Tags
    Circuit
AI Thread Summary
The circuit consists of a 1V voltage source, a 1A current source, and a 1 Ohm resistor in parallel. The voltage across the resistor remains at 1V due to the current source, which provides 1A, satisfying Ohm's law. The voltage source does not supply or sink current, resulting in zero power associated with it. The current source delivers 1 Watt of power, while the resistor dissipates 1 Watt as well. The analysis confirms that the circuit operates correctly with the given components.
RyanSchw
Messages
36
Reaction score
0

Homework Statement



This should be a really easy circuit, but I need to see if I have it done right.

1V source, 1A source and a 1 Ohm resistor in parallel (forgot to write the 1 Ohm resistor on the image.)

Find the power of each element.
http://img403.imageshack.us/f/circuit1.jpg/


Homework Equations



Ohm's law, KCL, KVL


The Attempt at a Solution



attached.

this just seemed kinda counter intuitive since it appears that there is no current running through the 1v source. Any help would be greatly appreciated.
 
Physics news on Phys.org
The original image has disappeared, so here's one based on the text description:
upload_2016-2-5_23-32-50.png


Currents have been indicated in anticipation of calculating the power associated with the components.

The voltage source will hold the potential across the 1 Ω resistor at 1 V. Ohm's law tells us that the current ##i_R## must be 1 Amp.

The current supply is pushing 1 Amp into the circuit, and this will satisfy the requirements of the 1 Amp through the resistor.

This leaves the voltage supply to consider. Note that it does not have to supply or sink any current in order for the potential across the resistor to remain at 1 V, since the current source is taking care of that. The voltage source could be removed from the circuit and the voltage drop across the resistor would remain at 1 V.

Now for the power produced or consumed by the components. Since the voltage supply is not passing any current there is no power associated with it. It neither produces nor consumes any power.

The current supply is producing 1 Amp at 1 Volt, so it is producing 1 Watt of power to the circuit.

The resistor is carrying 1 Amp of current and producing a 1 Volt potential drop in the direction of the current flow, so it is dissipating 1 Watt of power (the same power that the current source is injecting into the circuit).
 

Attachments

  • upload_2016-2-5_23-27-27.png
    upload_2016-2-5_23-27-27.png
    2.7 KB · Views: 355
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top