Quick Circuit Question (1 Viewer)

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1. The problem statement, all variables and given/known data

4189337838_b8b111fd5b_o.jpg


2. Relevant equations

KCL / KVL
V = IR

3. The attempt at a solution

[Edit] Nevermind, I got it. I don't know what the heck I was trying to do.

For future reference, in case someone needs to know, this is how it's solved:

V1 = 4*I
V2 = -2*I

-10 + V1 - 8 - V2 = 0
V1 - V2 = 18
(4*I) - (-2*I) = 18
6*I = 18
I = 3

V1 = 4*(3) = 12 V
V2 = -2*(3) = -6 V
 
Last edited:

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