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Quick Introduction to Tensor Analysis

  1. Mar 17, 2004 #1


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    Ruslan Sharipov has a nifty online textbook on this subject. It's written in interactive do-it-yourself style. Give it a glance, and see what you think.
  2. jcsd
  3. Mar 17, 2004 #2
  4. Mar 22, 2004 #3
    Thanks, Selfadjoint, I guess that now I comprehend better what tensors are. I printed the document out.
    I comprhend what vectors and covectors are, and comprhend the rules of transformations between different bases. ALso, more or less have an idea about what linear operators and bilinear forms are. I have problems comprhending the rules of transformations of linear operators between different bases, I refer explicitly to page 20, that says that a linear operator [itex]F_{j}^{i}[/itex] transforms to another basis as

    \bar{F}_{j}^{i} = \sum_{p=1}^{3} \sum_{q=1}^{3}
    {T_{p}^{i} S_{j}^{q} F_{q}^{p}}

    So, how do you get to the Ti p,Sq j and Fp q in the right side of the equality? I feel that i'm on the brim to completely understand tensor calculus, only have to work in a little details
  5. Mar 24, 2004 #4
    When learning tensor analysis/differential geometry it should be noted that there are two quite different things which are called "components" of a vector. The difference has to do with the difference between a natural (aka coordinate) basis and a non-natural basis. Unfortunately I haven't created a web page for this yet but its not that difficult to describe.

    Consider the vector displacement dr in an N-dimensional Euclidean space. Using the chain rule this can be expanded to read

    [tex] d\mathbf {r} = \frac {\partial \mathbf {r}} {\partial x^{i}} dx^{i} = dx^{i} \mathbf {e}_{i} [/tex]


    [tex] \mathbf {e}_{i} = \frac {\partial \mathbf {r}}{\partial x^{i}}[/tex]

    These form a set of vectors in which all other vectors may be expanded (i.e. a basis). These basis vectors are called natural basis vectors aka coordinate basis vectors. These basis vectors are not always unit vectors.
    Last edited: Mar 24, 2004
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