Quick Linear Algebra notation question

jofree87
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For transformations, what exactly does T(x) mean?

Does it mean T is the transformation matrix multiplied by a vector?

How about T(x1, x2) ?
 
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T(x) (or simply Tx) means the result of applying the transformation T to the vector x. If you have the coordinate representations of these objects, i.e., the matrix of T and the coordinates of the vector x, then the coordinates of the vector Tx are indeed given by multiplying the matrix of T by the coordinate vector of x, in that order.

If T happens to be a transformation whose domain space is two-dimensional, then T(x_1, x_2) probably means the result of applying T to the vector (x_1, x_2) where x_1, x_2 are numbers. If the domain space of T is other than two-dimensional, there is no obvious candidate for the meaning of T(x_1, x_2).
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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