R Network- finding total resistance.

AI Thread Summary
The discussion focuses on calculating the total resistance in a specific resistor network with R = R' = 1.97 Ω. Participants suggest using symmetry and voltage application to simplify the problem, particularly noting that certain resistors can be eliminated from calculations due to their equal values. One user initially struggles with a complex branch configuration but ultimately finds clarity by recognizing the voltage divider effect. The simplified approach leads to a more manageable calculation for resistance between points a and c. The conversation emphasizes the importance of recognizing symmetrical properties in resistor networks for easier analysis.
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Homework Statement


Assuming R = R' = 1.97 Ω in the network shown above, determine the net resistance

a) between the points a and c
b) between points a and b.
HELP: Use symmetry.
HELP: Imagine applying a voltage between a and c and think about what current will flow in each resistor.

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/Knox/phys130a/spring/homework/09/02/P26_36.jpg


Homework Equations


Series: Rtotal=R1+R2
Parallel: Rtotal=(R1-1+R2-1)-1


The Attempt at a Solution



Well, I redrew the series in my notebook as parallel and series, but in both attempts at a re-draw, I ended up with a weird branch that wasn't really either series or parallel, because of how it connected. I tried solving it anyway (and have come up with 1.313 for the resistance between a and c) but nothing's been right. I'm just not sure what to do with the weird branch. :/
 
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Observe that with all the resistors equal to each other that you can drop out the R' resistors that cross between the || branches. At each leg of your || you have a voltage divider with no net voltage across the R'. This should make your calculation a bit easier.

For instance between AC:

1/R + 1/2R + 1/2R = 1/Rac
 
Oh wow, that makes things a lot simpler. I wasn't aware that I could drop out that resistor. Thank you!
 
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