R through a wire: What's the max error in diameter if your R has 1% uncertainty?

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Homework Help Overview

The discussion revolves around determining the maximum error in measuring the diameter of a wire given a 1% uncertainty in its resistance. The context involves concepts from electrical resistance, resistivity, and geometric relationships in circular cross-sections.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss substituting the area of the wire into the resistance equation and explore the implications of resistance uncertainty on diameter measurements. There are attempts to solve the problem symbolically and questions about the relationship between calculated diameters and the original diameter.

Discussion Status

The discussion is active with participants providing clarifications and corrections regarding the resistance formula. Some guidance has been offered on how to approach the problem symbolically, and there is acknowledgment of potential errors in previous calculations.

Contextual Notes

Participants note the importance of considering the squared relationship of diameter in the resistance equation and question whether this affects the calculation of uncertainty. There is also mention of the need for precision in measurements.

anban
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Homework Statement



I have a wire of some resistance, resistivity, and length.

What is the maximum error in measuring the diameter that you can have if the resistance is to have 1% uncertainty?


Homework Equations



R = \frac{ρ*l}{\pi*r^{2}} for which I substituted the area as \pi(.5 D) ^{2}.


The Attempt at a Solution



I picked an arbitrary R and found the corresponding D. Then, I took 1% of that arbitrary R and found the corresponding D. The issue is that D's were basically the same number. I'm not sure if I could just go out to more decimal places or if I'm just wrong...
 
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anban said:

Homework Statement



I have a wire of some resistance, resistivity, and length.

What is the maximum error in measuring the diameter that you can have if the resistance is to have 1% uncertainty?

Homework Equations



R = \frac{Rρl}{\pi*r^{2}} .

The Attempt at a Solution



I picked an arbitrary R and found the corresponding D. Then, I took 1% of that arbitrary R and found the corresponding D. The issue is that D's were basically the same number. I'm not sure if I could just go out to more decimal places or if I'm just wrong...

You meant R = \frac{ρl}{\pi*r^{2}} , didn't you?

Solve the problem symbolically. If the resistance can differ from R by one percent it can be 1.01 R or 0.99 R. What are the corresponding diameters and how are they related to the original D? By what percent are they different from it? ehild
 
ehild said:
You meant R = \frac{ρl}{\pi*r^{2}} , didn't you?

Typo, thank you!

Solve the problem symbolically. If the resistance can differ from R by one percent it can be 1.01 R or 0.99 R. What are the corresponding diameters and how are they related to the original D? By what percent are they different from it?

Big help! Turns out I was off by a decimal point. My answer makes a lot more sense now. Thank you very, very much.
 
Another clarification-- the D in the denominator is squared. Does that mean I need to take the square root of my result?
 
What is your result at all?

ehild
 

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