Knowing that the diameter of the Earth at the equator is 12 740 km, compute the radial acceleration of a point on the surface of the Earth at the equator, due to the rotation of the Earth about its axis.
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Sorry!
I know that centripetal acceleration is v^2/r
The diameter of the earth is 12740 km, and half of that is the radius of 6370km.
How would I find v?
Angular velocity or w= the change in the angle of rotation/ change in time
Think about our earth making one complete rotation (how many radians is that?) divided by how long it takes to make that rotation in one day. Put that time in seconds.
Since you know the angular velocity multiply it by the radius to get Vt, the tangential velocity. Plug that value into V^2/r to get centripetal acceleration.