- #1

Amanda567

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- Thread starter Amanda567
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- #1

Amanda567

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- #2

RTW69

- 374

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What equations do you think might be useful for circular motion?

- #3

Amanda567

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I know that centripetal acceleration is v^2/r

The diameter of the earth is 12740 km, and half of that is the radius of 6370km.

How would I find v?

- #4

RTW69

- 374

- 1

You are getting closer. V is the tangential velocity, what is the equation for that?

- #5

Amanda567

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Would that be the period T, where that is the time to complete one revolution?

T=2pi(r)/v

T=2pi(r)/v

- #6

RTW69

- 374

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What is the definition of angular velocity? You will need the 2*pi for sure, what else?

- #7

Amanda567

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Angular velocity is what represents speed?

by: F=d/dt (mv)

by: F=d/dt (mv)

- #8

RTW69

- 374

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Think about our earth making one complete rotation (how many radians is that?) divided by how long it takes to make that rotation in one day. Put that time in seconds.

Since you know the angular velocity multiply it by the radius to get Vt, the tangential velocity. Plug that value into V^2/r to get centripetal acceleration.

I get 3.33 E-2 m/s^2

- #9

Amanda567

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What is E-2?

- #10

RTW69

- 374

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That means 3.33x10^-2 m/s^2 or 0.0333 m/s^2

- #11

Amanda567

- 10

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w=0.00007

0.00007(6370km)=0.46324km/sec

vt=0.46324km^2/6370

vt=0.0000336

Thats what i get, what am i doing wrong?

- #12

RTW69

- 374

- 1

Change KM to meters which means you multiply your final result by 1000

- #13

Amanda567

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thanks so much!!

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