Stress Distribution in Compound Cylinders

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SUMMARY

The discussion centers on the stress distribution in compound cylinders, specifically a thick elastic cylinder surrounded by a thin elastic band under internal pressure. The derived radial stress formula is given by \(\sigma_{rr} = -p\frac{\beta(1+(b/r)^2)+(1-(1-((b/r)^2)}{\beta(1+(b/a)^2)+(1-((b/a)^2)}\), where \(\beta\) is defined as \(\frac{(1-v^2)}{(1+v) v-(bE)(1-v_b^2)/(E_b h)}\). The participant initially attempted to solve for the interface pressure using Lame's equations but encountered errors due to applying plane stress conditions instead of plane strain. The correct interface pressure was derived by substituting the appropriate parameters for plane strain.

PREREQUISITES
  • Understanding of Lame's Equations for radial and tangential stress distributions.
  • Knowledge of elastic material properties, including Young's modulus (E) and Poisson's ratio (v).
  • Familiarity with the concepts of plane stress and plane strain in elasticity theory.
  • Basic skills in mathematical manipulation of equations involving stress and displacement.
NEXT STEPS
  • Study the derivation and application of Lame's Equations in cylindrical coordinates.
  • Learn about the differences between plane stress and plane strain conditions in elasticity.
  • Explore finite element analysis (FEA) techniques for stress distribution in composite materials.
  • Investigate the effects of varying material properties on stress distribution in compound cylinders.
USEFUL FOR

Mechanical engineers, materials scientists, and students studying elasticity and stress analysis in composite structures will benefit from this discussion.

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Homework Statement


A long, hollow, thick elastic cylinder (E , v) is surrounded by a thin elastic band of thickness t made of a different material (E_2 , v_2). The fit is ideal, such that neither a gap nor a pressure exists. An internal pressure p is then applied at the inside radius (r=a) of the thick cylinder. Assuming that the radial displacements is continuous at the interface (r=b), prove that the stress in the thick cylinder are given by
\sigma_{rr} = -p\frac{\beta(1+(b/r)^2)+(1-(1-((b/r)^2)}{\beta(1+(b/a)^2)+(1-((b/a)^2)}

where
\beta= \frac{(1-v^2)}{(1+v) v-(bE)(1-v_b^2)/(E_b h)}

Homework Equations


Lame's Equations. If a long cylinder is subject to internal pressure p_i at r_i and external pressure p_o at r_o then the radial stress distribution is

\sigma_{rr}=\frac{p_i r_i^2-p_o r_o^2}{r_o^2-r_i^2}+\frac{r_i^2 r_0^2(p_o-p_i)}{r^2(r_o^2-r_i^2)}

and the tangential stress distribution
\sigma_{tt}=\frac{p_i r_i^2-p_o r_o^2}{r_o^2-r_i^2}-\frac{r_i^2 r_0^2(p_o-p_i)}{r^2(r_o^2-r_i^2)}.

and finally the displacement is

u_r=\frac{1-v}{E}\frac{(p_i r_i^2 - p_o r_o^2)}{r_o^2-r_i^2} r + \frac{1+v}{E}\frac{r_i^2 r_o^2 (p_i-p_o)}{r_o^2-r_i^2}\frac{1}{r}.

The Attempt at a Solution



I attempted to match the displacements at the interface and solve for the interface pressure P. However, I can not get the correct solution with this approach.
The displacement of the inner cylinder at the interface is given by
u_r(r=b)=\frac{1-v}{E}\frac{(p_i a^2 - P b^2)}{b^2-a^2} b + \frac{1+v}{E}\frac{a^2 b^2 (p_i-P)}{b^2-a^2}\frac{1}{b}.

Canceling terms yields
u_r(r=b)=\frac{1}{E(b^2-a^2)}(2p_i a^2 b - (1-v)P b^3 - (1+v)P a^2 b)
The displacement at the interface of the outer cylinder is given by:

\sigma_\theta ≈ E \epsilon_\theta→ u(r=b) = \frac{Pb^2}{E_2 t}

because the outer elastic band is thin. Equating the displacements I get the interface pressure to

P = \frac{2 p_i a^2}{\frac{Eb(b^2-a^2)}{E_2 t}+(1-v)b^2+(1+b)a^2}.

I know this is the wrong interface pressure by check the solution given in the problem statement and through FEA analysis.
 
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Answer

There is a typo in my post above because (1+b) should be (1+v) in the denominator of the expression for P. The mistake I made was using the lame's equations for plain stress, while the problem wanted to plane strain solution. The expression for P matches the given result by making the plane stress to plane strain substitutions E\rightarrow E/(1-v^2) and v\rightarrow v/(1-v).
 
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