Radial distribution probability

hellomister
Messages
29
Reaction score
0

Homework Statement


When I'm trying to find the probability of finding an electron within a sphere of a certain radius, do i integrate the radial distribution probability function with respect to r from 0 to infinity? My book says the product of the radial distribution function times dr would give the probability, but I always thought you had to integrate it.


Homework Equations


n/a just looking for a simple answer to my question... i didnt show the homework problem cos i want to do it myself i just want this question answered.

The Attempt at a Solution


I've attempted the problem, i just integrated and I want to know if you should integrate.
 
Physics news on Phys.org
The probability of finding the particle in a shell of thickness dr having radius r is

dP=|\psi|^2\:4\pi r^2dr

The probability of finding the particle anywhere within a sphere of radius R is

P=\int^R_0 |\psi|^2\:4\pi r^2dr

Does this help?
 
yes! helps a ton! Thank you.
 
Notice that 4\pi r^{2} is the area of the surface of a sphere. This factor looks like that because you only have radial distribution, independent of azimuthal direction,
while if your wavefunction looks like \psi(r,\theta,\phi) things will get a little more complicated, and will involve additional integrations.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top