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bulbasaur88
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If an area of 1 m2 at the Earth surface emits Q/t = 54E-3 J/s in radiation, what would the temperature at the Earth surface be, if there would be no other energy sources? Assume that the Earth is a perfect black body emitter (e = 1).
Q/t = e(5.67E-8)(A)T4
54E-3 = 1(5.67E-8)T4
T = 31.2 K?
The answer is supposed to be 2.4 K? I feel pretty confident in my work so I am not certain where I have gone wrong.
Q/t = e(5.67E-8)(A)T4
54E-3 = 1(5.67E-8)T4
T = 31.2 K?
The answer is supposed to be 2.4 K? I feel pretty confident in my work so I am not certain where I have gone wrong.
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