Rate of change in temperature. Another way to do this?

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SUMMARY

The discussion focuses on solving a physics problem related to the rate of change in temperature, specifically using the equation Q = mc(deltaT) and its relation to power (P). The user initially calculated angular velocity and tangential velocity to determine power output, resulting in a value of 180 Watts. For the temperature change rate, they derived a rate of 0.064 C/s using the formula deltaT/t = P/mc. The consensus is that a calculus approach is unnecessary as the rate is constant, validating the user's method.

PREREQUISITES
  • Understanding of thermodynamics, specifically the equation Q = mc(deltaT)
  • Basic knowledge of angular motion and tangential velocity
  • Familiarity with power calculations in physics
  • Concept of calculus, particularly the chain rule
NEXT STEPS
  • Explore the application of the chain rule in thermodynamic problems
  • Study the relationship between power, work, and energy in physics
  • Learn about constant rates of change in calculus
  • Investigate advanced thermodynamic equations and their applications
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and angular motion, as well as educators seeking to clarify concepts related to power and temperature change rates.

navm1
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Homework Statement


[/B]
My question is regarding Part B of this problem, I have solved it but I'm wondering if there is another way to solve it since it says dtheta/dt and one of the hints I found online suggested that I use the chain rule.

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Homework Equations


Q = mc(deltaT)
Q/t = P

The Attempt at a Solution



For the first part, i just did theta/time to find angular velocity, then multiplied by radius to find the tangential velocity, then just multiplied by the force of 520N by pi/9, the tangential velocity to get 180 Watts.

For the second part I just divided the equation for Q by t to make deltaT/t=P/mc and got 0.064 C/s.

If there was a calculus way to solve this I'd appreciate some help. Thanks
 
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navm1 said:
For the second part I just divided the equation for Q by t to make deltaT/t=P/mc and got 0.064 C/s.

If there was a calculus way to solve this I'd appreciate some help. Thanks
There's no calculus of any interest here, the rate is constant. Your method is as good as any.
 
makes sense. thanks haruspex
 

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