Rate of change of radius through a a circular wire loop?

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To maintain zero induced emf in a circular wire loop with a radius of 19 cm in a decreasing magnetic field of 0.690 T at a rate of -1.0×10^-2 T/s, the area change rate must be calculated. The equation derived is 0 = (Bcos0)(dA/dt) + (Acos0)(dB/dt), leading to a calculated area change rate of 0.0016 m²/s. This translates to a radius change rate of 22.8 mm/s when converted to the appropriate units. The relationship between area and radius is established through the formula A = πr², which is used to derive the necessary rate of radius increase. The final result indicates that the radius must increase at a rate of 22.8 mm/s to keep the induced emf at zero.
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A circular wire loop of radius r = 19 cm is immersed in a uniform magnetic field B = 0.690 T with its plane normal to the direction of the field. If the field magnitude then decreases at a constant rate of −1.0×10^-2 T/s, at what rate should r increase so that the induced emf within the loop is zero?



Flux=BAcos(theta)
emf=dq/dt


I tried this and I got an equation of 0=(Bcos0)(dA/dt)+(Acos0)(dB/dt)
and I plugged it into get dA/dt=.0016m^2/s and then i solved for the radius in this case which is .0228m and my answer is supposed to be in mm/s so i got 22.8 mm/s as my answer.
 
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Area = πr^2.
hence dA/dt = 2πr*dr/dt.
Now find dr/dt.
 
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