Rate of Reaction: Effects of Volume Changes

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Increasing the volume of potassium iodate or sodium hydrogen sulfite generally increases the reaction rate due to higher concentrations of reactants, which enhances the likelihood of collisions. Using too much starch indicator may not directly affect the reaction rate but could complicate the observation of results. Conversely, decreasing the volume of either reactant is likely to slow the reaction due to lower concentrations. The relationship between volume and reaction rate is tied to the principles of concentration and collision theory. Ultimately, conducting experiments is essential to accurately determine these effects in practice.
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If i were to increase to react potassium iodate with sodium hydrogen sulphite at room temperature, what would happen to the rate of react and why if:

1) i increased the volume of iodate solution added
2) increased the volume of the sodium hydrogen sulhpite solution.
3) used too much starch indicator
4) decreased the volume of iodate solution added
5) decreased the volume of the sodium hydrogen sulhpite solution.

I have a lab due monday and my teacher doesn't teach us a thing! Thanx a bunch!
 
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Strictly speaking, you can not predict the effect of concentration on the reaction rate, and will have to do an experiment to determine this. In most cases, however, you can expect the reaction rate to depend directly on the concentrations of the reactants.

So, is this a question from a lab that you've already done, or for a lab that you are going to do ? The KIO3 + NaHSO3 rection is often used for labs where you are asked to determine the rate equation from the experiments. Is this what the lab is about ? If so, the question must be answered using the results of the lab.
 
Ya but I'm talking about volume, not concentration. If, for example, i used more sodium hydrogen sulphite, what would happen?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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